Hi all,
I am trying to rename a zip file with the user input. I have tried but when i am giving the variable its making a file with the vairiable name only like $abc not with the value stored in the variable.
#!/bin/perl
use strict;
use warnings ;
use Archive::Zip;
my $zip_file = 'file.zip' ;
my $zip = Archive::Zip-> new ();
$zip ->addTree( 'c:/zip');
$zip ->writeToFileNamed( $zip_file );
if (-e $zip_file) {
print "Archive created successfully!";
} else{
print "Error in archive creation!";
}
Instead of $zip_file being hardcoded i want to take user input for the zip file name.
I am using the following code
#! usr/bin/perl
use Archive::Zip;
# Getting Details
print "Enter the Folder Name \n";
$rn = <>;
print "The details are as follows: \n";
print "Release Name is *** $rn *** \n";
print "Business Unit is *** ABC *** \n";
print "Environment is *** ABC *** \n";
# Taking Backup
my $zip_file = 'file.zip';
my $zip = Archive::Zip-> new ();
$zip ->addTree( 'c:/zip');
$zip ->writeToFileNamed($zip_file);
if (-e $zip_file) {
print "Archive created successfully!";
} else{
print "Error in archive creation!";
}
here i am taking the input from the user and storing it in a variable $rn now i want to make the zip file with the name stored in the variable $rn.
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