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Why do we say the =~ operator "binds"?by Cody Pendant (Prior)
|on Apr 18, 2004 at 03:30 UTC||Need Help??|
Cody Pendant has asked for the
wisdom of the Perl Monks concerning the following question:
Not exactly a mission-critical question, but it's been puzzling me for a while.
Why do the docs say that
Binary "=~" binds a scalar expression to a pattern match.
I just don't really understand the way in which the word "bind" is being used there.