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How to escape special characters correctly for a URL

by silent11 (Vicar)
on May 27, 2004 at 13:34 UTC ( #356890=perlquestion: print w/replies, xml ) Need Help??
silent11 has asked for the wisdom of the Perl Monks concerning the following question:

What I have: Fútbol con Mayte introducción al fútbol

What I need: F%C3%BAtbol+con+Mayte+introducci%C3%B3n+al+f%C3%BAtbol

What I get with URI::Escape : F%FAtbol%20con%20Mayte%20introducci%F3n%20al%20f%FAtbol

What module can I use to convert what I have, a string with those funky characters, into what I need, an escaped sequence? URI::Escape isn't doing the job for me, I'm sure it is doing it's job correctly, I'm just misusing the module. Any Ideas?


-silent11
  • Comment on How to escape special characters correctly for a URL

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Re: How to escape special characters correctly for a URL
by snadra (Scribe) on May 27, 2004 at 14:57 UTC
    URI::Escape is using RFC2396 and updated by RFC2732 for encoding and decoding characters that are not alphanumeric (a-zA-Z_0-9 or simply \w).
    Try to figure out what kind of encoding you have to use. Maybe there is an existing module. If not a definition will make it easier for you to write one.

    snadra
Re: How to escape special characters correctly for a URL
by Roy Johnson (Monsignor) on May 27, 2004 at 14:21 UTC
    You're not misusing the module; it seems you don't want the module. If you pass your "what I need" to uri_unescape, you get a mess, so it's clearly not compatible. (At the very least, the spaces-for-pluses translation isn't normal.)

    I think you're going to have to roll your own. How did you determine what you need?


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Node Type: perlquestion [id://356890]
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[Eily]: you could tie a variable into not having the same value each time, if you like to make people who try to debug your code facepalm
[Corion]: perl -wle 'package o; use overload q("") => sub {warn "str"; ""}, bool => sub{warn "bool"; 1}; package main; my $o={}; bless $o => o; print "Yay" if ($o && !length($o))'
[Corion]: But people writing such code should document the objects they construct and why it makes sense for an object to be invisible as string while being true in a boolean context
[hippo]: That's equal parts clever and horrendous.
[Eily]: the overload version wouldn't return true with "$x" && !length $x though, I guess
[hippo]: The more I look at this code, the more $x is a plain old scalar and the more this condition will never be true. I'm calling it a bug at this point.
[hippo]: Thanks for your input which has soothed my sanity (a little)
[Corion]: Eily: Sure - if you force both things into stringy things, then you break that magic. But that would also mean that you changed the expression, as now $x = 0.00 will be true instead of false as it were before
[Corion]: Ah no, at least in my feeble experiments that doesn't change the meaning
[Corion]: We sell sanity in small packages ;)

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