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Re: Matching Newlines in RegExp

by orderthruchaos (Scribe)
on Jun 14, 2004 at 19:50 UTC ( #366674=note: print w/replies, xml ) Need Help??

in reply to Matching Newlines in RegExp

I agree with the prior replies... I'm not exactly sure what you are looking for... I tried out your code on a fairly simple example and it seems to work fine:
#!/usr/bin/perl -w use strict; my $e = '\\'; # kind of escape char my $s = '\''; # this is a string to use for splitting my $str = "this \n contains \\'\n new lines " . "and single'\nquotes'\n more than\' once"; if( $str =~ m#$/# ) { $s .= "$/"; # ?? right so? } my $re = qr/(?<!\Q$e\E)\Q$s\E/; my @parts = split $re, $str; print scalar(@parts), "\n"; for ( my $i = 0 ; $i < @parts ; $i++ ) { print "$i: $parts[$i]\n"; }
gives the following output:
% ./ 3 0: this contains \' new lines and single 1: quotes 2: more than' once
The string was split on '\n, but not \'\n, \n or '.

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