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Re: How's your Perl? (II)

by Errto (Vicar)
on Jul 22, 2004 at 03:59 UTC ( #376456=note: print w/ replies, xml ) Need Help??


in reply to How's your Perl? (II)

Update:modified slightly.

6:
my @foo = (0); $[ = -1;


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Re^2: How's your Perl? (II)
by eric256 (Parson) on Jul 22, 2004 at 04:07 UTC

    That doesn't seem to work here.


    ___________
    Eric Hodges
      I modified it slightly. I'm running: This is perl, v5.8.3 built for i386-linux-thread-multi
Re^2: How's your Perl? (II)
by mauke (Novice) on Jul 22, 2004 at 06:26 UTC

    Confirmed on 5.6.1, 5.8.0, 5.8.1, 5.8.3. Doesn't work on 5.8.4 and 5.8.5.
    And I think it should not work, because $foo[$[] is the first element and $foo[$[+1] is the second; I don't see how $[ and $[+1 can refer to the same element.

    All exercises have been tested with perl 5.8.*, and solutions do not necessarily have to work with any other version.

    I take this to imply that solutions should work with all 5.8.* perls.

      Hm, strange.. I actually wrote $foo[$[] in the assuption this would prevent any $[-fiddling and force the real solution, but it seems $[ really doesn't work properly in perl: perl -le '$[ = -1; @x = (42); $y = 0; print $x[$y]' prints 42 for me on 5.8.3 and 5.8.4...

      I'll add a note to the exercise that the intention is to solve it without diddling $[

      Fair enough. My only excuse is that 5.8.3 is the only version I have, and that the other way seemed too similar to one of the solutions from last time around so I wanted to try something different :) I was trying to use the fact that $foo[-1] is the last element in the array, so if the array only has one element ...

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