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Re^6: Smart match in p5

by xmath (Hermit)
on Mar 14, 2005 at 18:09 UTC ( #439388=note: print w/ replies, xml ) Need Help??


in reply to Re^5: Smart match in p5
in thread Smart match in p5

If you had bothered to read the original meditation, you'd have seen the remark:

Note that prefix '~~' still works like it did previously. Therefore if foo is a sub, then foo~~bar will be parsed as foo(~~bar) unless foo has prototype ().
To get a smartmatch on the result of foo, you'd write foo() ~~ $var


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