in reply to Re^5: Smart match in p5
in thread Smart match in p5
If you had bothered to read the original meditation, you'd have seen the remark:
Note that prefix '~~' still works like it did previously. Therefore if foo is a sub, then foo~~bar will be parsed as foo(~~bar) unless foo has prototype ().To get a smartmatch on the result of foo, you'd write foo() ~~ $var
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