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Re: How to flatten hashes?

by tlm (Prior)
on Jul 14, 2005 at 13:13 UTC ( #474859=note: print w/replies, xml ) Need Help??


in reply to How to flatten hashes?

FWIW,

use strict; use warnings; my %hash = ( accesslevels => { function => { func1 => { content => 'val1 +' }, default => { content => 'val2 +' } } } ); sub flatten { my $hash = shift; while ( my ( $k, $v ) = each %$hash ) { next unless ref $v eq 'HASH'; flatten( $v ); exists $v->{ $_ } and $hash->{ $k } = $v->{ $_ } for qw( function content ) } } use Dumpvalue; flatten( \%hash ); print Dumpvalue->new->dumpValue( \%hash ); __END__ 'accesslevels' => HASH(0x814cad4) 'default' => 'val2' 'func1' => 'val1'

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[Corion]: But maybe there is some other Unicode string that will be true but have a zero width
[hippo]: For explanation, I've seen this construct in someone else's code (no names, no pack drill) and couldn't think of a situation to trigger it.
[Corion]: You'll have to look somewhere esoteric for that. Maybe some tied variable or special dualvar can also trigger that. But it's certainly not a common occurrence
[Corion]: And on 5.20, the following also outputs no find:perl -wle 'for my $x ("\x{2000}".."\ x{1fffff}") { if( $x && ! length $x ) { warn qq(<$x>); warn length $x; die } }'
[Corion]: (this time on Unix)
[hippo]: Understood. I'll have to go through the code and see if it's doing anything fancy with ties, dual-vars or non-scalars. In the end, it's probably a bug though.
[Corion]: Aaah - you should be able to do this with overload, but I would hit somebody really hard if they constructed objects that are true but the empty string, and you not knowing about the domain knowledge where this makes sense

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