in reply to Re: Algorithm for cancelling common factors between two lists of multiplicands in thread Algorithm for cancelling common factors between two lists of multiplicands
Here is my shot at a pseudocode
1. Pick the first element of array a
2. Calcuate the GCD(a[0],b[0]) or better yet a[0] = mod (a[0], gcd(a[0],b[0]) and b[0] =mod (a[0], gcd(b[0],b[0]) (just divide elements by gcd, it should be an integer)
3. If anything is 1 pop it out of the list
4. Go through the list of elements for b with a[0] again. Do this until all elements are scanned in b.
5. Take the second element in a and repeat the process.
Does this work?
I shall post the code if i get a chance to implement it
SK
PS: This reminds of division in high school days ;)
Re^3: Algorithm for cancelling common factors between two lists of multiplicands by BrowserUk (Pope) on Aug 08, 2005 at 20:50 UTC 
PS: This reminds of division in high school days ;)
I guess that's where the "cancelling out" phrase comes from :)
Maybe the confusion comes from the fact that most people younger than me never learned to cancel out their equations because they all used calculators from an early age.
They probably don't know what "casting out the nines" is either.
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