Re: Shortcut operator for $a->{'b'}=$b if $b;

Ugly, but short:

$_ and $a->{b} = $_ for $b;
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Comment on Re: Shortcut operator for $a->{'b'}=$b if $b; Download Code

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Re^2: Shortcut operator for $a->{'b'}=$b if $b; by chester (Hermit) on Sep 20, 2005 at 16:43 UTC
What's the `for` doing, there? Doesn't this work? ~~`$b and $a->{'b'} = $b`~~ edit: Doesn't solve the problem fully.	[reply] [d/l] [select]
Re^3: Shortcut operator for $a->{'b'}=$b if $b; by merlyn (Sage) on Sep 20, 2005 at 16:48 UTC
I thought the point was that $b was standing in for something very complex or impossible to repeat for calculation. -- Randal L. Schwartz, Perl hacker Be sure to read my standard disclaimer if this is a reply.	[reply]
Re^4: Shortcut operator for $a->{'b'}=$b if $b; by chester (Hermit) on Sep 20, 2005 at 16:50 UTC
Ah, I see. My mistake.	[reply]
Re^3: Shortcut operator for $a->{'b'}=$b if $b; by ikegami (Patriarch) on Sep 20, 2005 at 16:48 UTC
foreach loops sets $_ to refer to the current value in the list which is being iterated. In this case, the list consists solely of $b. Your expression is equivalent, but it's not an acceptable answer since the question was about removing the need for using $b twice.	[reply]


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