Re: Quick easy question: What does $i mean?

[sicone]

Thanks, I believe that it is the loop name here is a specific example

my ($i);
for  ($i = 0; ($i < int (@commandsProperOrder)); $i += 2) {
       $commandsProperOrder{$commandsProperOrder[$i]}=
               $commandsProperOrder[$i + 1];
}

this code is full of $i's

[QM]

First off, you'll want to learn how to post here. If you put your code between "<code>" and "</code>" tags, then normal code punctuation is escaped for you. So this:

my ($i); for ($i = 0; ($i < int (@commandsProperOrder)); $i += 2) { $commandsProperOrder{$commandsProperOrder$i} = $commandsProperOrder$i + 1; }

looks like this:

my ($i); 
for ($i = 0; ($i < int (@commandsProperOrder)); $i += 2) {
$commandsProperOrder{$commandsProperOrder[$i]}
  = $commandsProperOrder[$i + 1]; 
}

(OK, I had to break some lines because of the long variable names, but otherwise it came out as typed.)

Second, I'd guess that the array @commands has a list of pairs, and that the code is trying to put those pairs into the hash %commands. Normally you want to know (or check) that your array is appropriate for this, but hash stuffing is more easily done with:

%commands = @commands;

No $is, etc., just Perl magic.

This works because a list can be assigned to a hash, and it will (sometimes) do the right thing. (It's certainly no worse than the code you posted.) [When you're ready, just ask, someone will tell you when and why it doesn't do the right thing.]