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Re: 0 illegal modulus?

by ambrus (Abbot)
on Sep 25, 2005 at 21:56 UTC ( #494969=note: print w/replies, xml ) Need Help??


in reply to 0 illegal modulus?

The same thing is also discussed in Re: Illegal Modulus zero.

Replies are listed 'Best First'.
Re^2: 0 illegal modulus?
by Anonymous Monk on May 01, 2012 at 03:35 UTC

    This seems to work great, thank you!

    #use DateTime::Util::Calc qw(mod); #sub mod { $_[1]*1 ? $_[0] % $_[1] : 0);} sub mod { my($x)=$_[0]; my($y)=$_[1]; while($x >= 0){ $x-=$y; } $x+=$y; return($x); }

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