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Re^2: Reading (and parsing) a byte stream

by ChemBoy (Priest)
on Mar 06, 2006 at 03:57 UTC ( #534630=note: print w/ replies, xml ) Need Help??


in reply to Re: Reading (and parsing) a byte stream
in thread Reading (and parsing) a byte stream

I'm afraid your shot misses—endianness has to do with byte order, not the significance of bits within bytes. So if you have a four-byte number, the most-significant byte may be at the beginning (Big-endian, or $Config{byteorder} eq '4321') or at the end (Little-endian, '1234'), but the values of the bytes themselves don't change.



If God had meant us to fly, he would *never* have given us the railroads.
    --Michael Flanders


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Re^3: Reading (and parsing) a byte stream
by acid06 (Friar) on Mar 06, 2006 at 04:12 UTC
    Not really.
    From the article about Endianness at the Wikipedia:

    Endianness also applies in the numbering of bits within a byte or word. In a consistently big-endian architecture the bits in the word are numbered from the left, bit zero being the most significant bit and bit 7 being the least significant bit in a byte.

    So endianness should have to do with bit order.
    Just because the usual way of packing/unpacking little- or big-endian data in Perl (Network and VAX types) does not follow this pattern it doesn't mean it's not correct.


    acid06
    perl -e "print pack('h*', 16369646), scalar reverse $="

      Bit order only matters if you've got a way of addressing things smaller than bytes or if you've encoded bits from one byte into multiple bytes. That isn't the case here so bit order should not matter. The data is transmitted in units of bytes and thus the values of the bytes are preserved, no matter how each unit along the way chooses to store those byte values.

      - tye        

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