Re^2: Equality operators

Mantadin, thank you. I am aware of this, however I am wondering why '1' == '1foo' evals to true while '1' eq 'foo1' does not.

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Re^3: Equality operators by davorg (Chancellor) on Apr 25, 2006 at 11:44 UTC
When converting strings to numbers, Perl only looks at the start of the string. '1foo' becomes 1 and 'foo1' becomes 0. -- <http://dave.org.uk> "The first rule of Perl club is you do not talk about Perl club." -- Chip Salzenberg	[reply]
Re^3: Equality operators by salva (Monsignor) on Apr 25, 2006 at 11:46 UTC
because strings are automatically converted to numbers when needed. `'1foo'` is converted to `1` and `'foo1'` is converted to `0`.	[reply] [d/l] [select]
Re^3: Equality operators by ikegami (Pope) on Apr 25, 2006 at 14:44 UTC
Others have already explained how the conversion works, but if you want to see for yourself the number into which a string is coerced, add 0 to the string. `print(0+'a', "\n"); # 0 print(0+'b', "\n"); # 0 print(0+'1', "\n"); # 1 print(0+'2', "\n"); # 2 print(0+'1foo', "\n"); # 1 print(0+'foo1', "\n"); # 0` [download]	[reply] [d/l]