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Move matched to top, bottom

by quinkan (Monk)
on May 02, 2006 at 22:36 UTC ( [id://547006]=perlquestion: print w/replies, xml ) Need Help??

quinkan has asked for the wisdom of the Perl Monks concerning the following question:

I had a need to "float" entries matchable with a regex to the bottom of an array or list, preferably without altering the order of other entries. I played for a while with split and splice, but reached the conclusion that the following works for my purposes...

my @rawentries = ( "1topEndbit", "2ndbit", "endBit3", "4thbit", "5thbit", "6OtherEndbit", "7Bitsecondfromend", "8Bitoneoffend", "9Anyoldbit", ); sub ToTop { my $t1 = ($a =~ m/Endbit/i)? 0:1; my $t2 = ( $b =~ m/Endbit/i )? 0:1; $t1 <=> $t2; } sub ToEnd { my $t1 = ($a =~ m/Endbit/i)? 1:0; my $t2 = ( $b =~ m/Endbit/i )? 1:0; $t1 <=> $t2; } my @toendlist = sort ToEnd @rawentries; my @totoplist = sort ToTop @rawentries; print (join "\n", @toendlist); print "\n\n".join ("\n", @totoplist)."\n";
Two questions arise:

  1. Can this sort usage be relied upon?
  2. Am I missing obvious alternative(s) ?

Replies are listed 'Best First'.
Re: Move matched to top, bottom
by GrandFather (Saint) on May 02, 2006 at 22:51 UTC

    The following may appeal:

    use strict; use warnings; my @rawentries = ( "1topEndbit", "2ndbit", "endBit3", "4thbit", "5thbit", "6OtherEndbit", "7Bitsecondfromend", "8Bitoneoffend", "9Anyoldbit", ); my @sorted; my @last; /Endbit/i ? push @last, $_ : push @sorted, $_ for @rawentries; push @sorted, @last; print join "\n", @sorted;

    Prints:

    2ndbit 4thbit 5thbit 7Bitsecondfromend 8Bitoneoffend 9Anyoldbit 1topEndbit endBit3 6OtherEndbit

    DWIM is Perl's answer to Gödel
      Thanks for that. Looks a good deal faster, too (which I guess is to be expected when a sort is involved, particularly if we start with initially-sorted or close-to-sorted data -- even with median partition selections).

      Oops ! I see 5.8 has changed sort to allow a change from the quicksort to mergesort, so median-of-three need not be the point.. (Thanks for the pointer, Tanktalus.)

Re: Move matched to top, bottom
by Tanktalus (Canon) on May 03, 2006 at 00:41 UTC
    Can this sort usage be relied upon?

    No, not entirely. You're asking that no other entries change places with respect to each other, except on the criteria of matching some regex (in your example, /Endbit/i). That requires a stable sort, which perl does not entirely guarantee in all circumstances. Look at the sort documentation and search for the word 'stable' to see what this means, and how you can get a stable sort at all times.

    Am I missing obvious alternative(s) ?

    I think the most obvious solution is just to seperate out all the entries into two arrays, and then merge them together afterwards. Something like this:

    my (@match, @notmatch); for (@rawentries) { if (/Endbit/i) { push @match, $_; } else { push @notmatch, $_; } } my @newlist = (@notmatch, @match); # the ones that match float to the +bottom
    That's not to say this is the most efficient algorithm - but you asked for obvious ;-)

Re: Move matched to top, bottom
by johngg (Canon) on May 03, 2006 at 08:58 UTC
    As per davidrw's suggestion, here is a Schwartzian Transform to do the same thing.

    use strict; use warnings; my @rawentries = ( "1topEndbit", "2ndbit", "endBit3", "4thbit", "5thbit", "6OtherEndbit", "7Bitsecondfromend", "8Bitoneoffend", "9Anyoldbit"); print map {"$_->[0]\n"} sort { $a->[1] <=> $b->[1] || $a->[2] <=> $b->[2] } map { [ $rawentries[$_], $rawentries[$_] =~ /Endbit/i ? 1 : 0, $_ ] } 0 .. $#rawentries;

    When run it produces

    2ndbit 4thbit 5thbit 7Bitsecondfromend 8Bitoneoffend 9Anyoldbit 1topEndbit endBit3 6OtherEndbit

    Cheers,

    JohnGG

Re: Move matched to top, bottom
by davidrw (Prior) on May 03, 2006 at 01:31 UTC
    This should do it .. read the comments backwards.
    print join "\n", @rawentries[ # array slice to turn the indices back to the values (c +ould use map, too) sort { ($rawentries[$a] =~ /Endbit/i) <=> ($rawentries[$b] =~ m/Endbi +t/i) # sort first using the index's array value matching against a r +egex and sort against the return. non-matches go higher; matches go l +ower || $a <=> $b # default to just sorting the index values to + maintain order w/in bit/not-bit chunks } 0 .. $#rawentries # sort the indices ] ;
    (note that this could be a good candidate for a schwartzian transform)

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