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Re: Things you need to know before programming Perl ithreads

by jdhedden (Deacon)
on May 16, 2006 at 14:21 UTC ( #549776=note: print w/replies, xml ) Need Help??


in reply to Things you need to know before programming Perl ithreads

use threads (); my $thread; BEGIN { # execute this at compile time $thread = threads->new( sub { print "Benchmark has not been loaded!\n" unless defined $Bench +mark::VERSION; # do your Benchmark stuff } ); } use Benchmark; $thread->join;
which prints:
Benchmark has not been loaded!
Scalars leaked: 1
Yikes! What is that! "Scalars leaked: 1". Well, yes, that's one of the remaining problems/features/bugs of the Perl ithreads implementation. This particularly seems to happen when you start threads at compile time. From practical experience, I must say it seems to be pretty harmless.
The leaked scalar is the result of returning a closure from a thread. In many cases it is, as mentioned, harmless. However, in some implementations of Perl, returning a closure from a thread may cause the interpreter to crash (i.e., dump core). Caveat emptor.

Remember: There's always one more bug.

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[shmem]: Re^5: Understanding endianness of a number - nice! "zigamorph" will be the host name of the VM I'll set up to debug Microfocus COBOL/perl stuff :-D
[prospect]: Hi, to avoid cluthering the Seekers of Perl Wisdom page. I wanted to print out the values on a new line each. So I though I put a . "\n" behind "print foreach func()" but something interesting happens and it I just get "5" as output :p
[prospect]: print foreach func(). "\n"; sub func { return ( 1, 2, 3, 4, 5 ); }
[prospect]: if I remove the ".\n" I get "12345" as output

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