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Re^4: Reverse engineering a formula...

by devnul (Monk)
on Jun 13, 2006 at 10:34 UTC ( #554994=note: print w/ replies, xml ) Need Help??


in reply to Re^3: Reverse engineering a formula...
in thread Reverse engineering a formula...

Not every number necessarily needs to be part of the formula (obviously its 2 or more numbers in some combination of addition and/or subtraction). Those two numbers could simply not be part of the formula.

- Devnul


Comment on Re^4: Reverse engineering a formula...
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Re^5: Reverse engineering a formula...
by Skeeve (Vicar) on Jun 13, 2006 at 10:41 UTC
    As I said before: Not enough information...

    It seems as if your formular is something like this (untested code of course):
    my @sign=( .... ); # Some combination of -1, 0 1 my @sum= map { $sign[$i] * $VAR1[$i] } (0..$#VAR1); print eval join ' + ', @sum;
    Now you "only" need to get the correct combination of -1, 0 and 1 for @sign, which is a "simple" combinational task but will be very lengthy...

    s$$([},&%#}/&/]+}%&{})*;#$&&s&&$^X.($'^"%]=\&(|?*{%
    +.+=%;.#_}\&"^"-+%*).}%:##%}={~=~:.")&e&&s""`$''`"e

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