Re^4: Secret Perl Operators: the boolean list squash operator, x!!

[Jenda]

in reply to Re^3: Secret Perl Operators: the boolean list squash operator, x!!
in thread Secret Perl Operators: the boolean list squash operator, x!!

I see. Actually to prevent confusion ... even this would autovivify:

@a  = ( $hash{foo}{bar} x!! 0);

I guess we'd need to "fix" the x operator to not evaluate the lefthand operator if the righthand one is <=0.