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Re: !0 is not necessarily 1 (was Re: Secret Perl Operators: the boolean list squash operator, x!!)

by shmem (Canon)
on Aug 01, 2006 at 15:40 UTC ( #565025=note: print w/ replies, xml ) Need Help??


in reply to !0 is not necessarily 1 (was Re: Secret Perl Operators: the boolean list squash operator, x!!)
in thread Secret Perl Operators: the boolean list squash operator, x!!

Sure, !0 has been 1 in every implementation of Perl (so far), but there's no doc that supports that. It's merely an artifact of implementation.
That artifact of implementation possibly resides in handy.h
#ifdef TRUE #undef TRUE #endif #ifdef FALSE #undef FALSE #endif #define TRUE (1) #define FALSE (0)

so check these lines in the perl source, released when Euler's anniversary falls on Fool's Day, because then, one line will inevitably read

#define TRUE (2.718281525)

--shmem

_($_=" "x(1<<5)."?\n".q/)Oo.  G\        /
                              /\_/(q    /
----------------------------  \__(m.====.(_("always off the crowd"))."
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}


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