(OT) Fibonacci numbers in Ruby - final shot - 24 chars

[sh1tn]

#!/usr/bin/env ruby
x=i=1;p x+=i=x-i while+1

2006-11-17 Retitled by Arunbear, as per Monastery guidelines
Original title: 'Fibonacci numbers - final shot - 24 chars'

[ambrus]

Meh, if you don't have to use perl, you can do much better: Re: Fibonacci numbers (again).

Update: let's put them under each other to see which one is longer.

         1         2         3
123456789012345678901234567890123
dc -e1d[pdsd+ldrlxx]dsxx
ruby -e'x=i=1;p x+=i=x-i while+1'

[ambrus]

It's also easy to shorten the ruby version by two characters

x=i=1;loop{p x+=i=x-i}

[ikegami]

That's 33, not 24 (since omitting the first line gives a compile error).

If you want really small, try 4!

do f

I'm sure f can be made way smaller than ruby.

Update: Downsized from 10