Re^4: Conditional Operator Confusion

[Melly]

Not really... I'm sure I'm being really dumb here, but I still don't understand, in the following example, why $x gets set to "FALSE"... just very, very confused...

1==1?$x='TRUE':$y='FALSE';
print "x=$x\n";

[ikegami]

The conditional operator has higher precedence than the assignment operator, so
$c?$x='TRUE':$y='FALSE'
is the same as
($c?$x='TRUE':$y)='FALSE'

The addition operator has higher precedence than the conditional operator, so
$c?$x+2:$y+3
is the same as
$c?$x+2:($y+3)

If you want to do assignments, use if or add parens. Think of as the conditional operator as an operator that returns something.

[Melly]

Thanks - I think I've finally got it (with some help from the chatterbox as well).

All of which goes to confirm something a coworker once told me..

Me: What's the precedence in <lang> for these operators?
CW: Who cares? Use brackets - it's easier to read and
    you won't get screwed...