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Re: differences between eq "" and !

by imp (Priest)
on Dec 14, 2006 at 04:08 UTC ( #589741=note: print w/replies, xml ) Need Help??


in reply to differences between eq "" and !

The value obtained by using an array in scalar context is the number of entries in that array - and an empty string is not a number.

Neither test in the code you provided will print anything, as it is equivalent to this:

if (0 eq "") { print "TEST1 passed\n"; } if (0) { print "TEST2 passed\n"; }

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[shmem]: try it out:
[Lady_Aleena]: shmem, thanks. I'm am way out of practice.
[shmem]: perl -lE '@foo = (0..3);@bar = (4..7); push @foo,@bar; say for @foo'
[Lady_Aleena]: shmem, I feel like an idiot for forgetting something so basic.
shmem puts a big cauldron of "silly con charme" on the table in the refectorium
[reisinge]: 'push @foo, @bar' is the same as '@foo = (@foo ,@bar)' ?

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