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Answer: How can I find the index of the biggest element in an array?

( #617760=categorized answer: print w/ replies, xml ) Need Help??

Q&A > arrays > How can I find the index of the biggest element in an array? contributed by Skeeve

my $i = $#data; my $max = $i; $max = $data[$i] > $data[$max] ? $i : $max while $i--; print "Max value is $data[$max], at index $max\n"

Comment on Answer: How can I find the index of the biggest element in an array?
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Re: Answer: How can I find the index of the biggest element in an array?
by Skeeve (Vicar) on May 27, 2007 at 19:40 UTC

    Oops! Little Problem! Replace "scalar @data" with "$#data"

    Update: Fixed by jdporter deletion of this node is okay with me...


    s$$([},&%#}/&/]+}%&{})*;#$&&s&&$^X.($'^"%]=\&(|?*{%
    +.+=%;.#_}\&"^"-+%*).}%:##%}={~=~:.")&e&&s""`$''`"e
Re: Answer: How can I find the index of the biggest element in an array?
by Jenda (Abbot) on May 28, 2007 at 14:09 UTC

    I don't think it's good to scare people with a ternary operator and statement modifier in one statement. I do think

    while ($i--) { $max = $i if $data[$i] > $data[$max]; }
    would be much more readable. I'd probably write it like this though:
    my $max = 0; for (0 .. $#data) { $max = $_ if $data[$_] > $data[$max] }

    Update (suggested by ysth): It's actually better to start looping at index 1:

    my $max = 0; for (1 .. $#data) { $max = $_ if $data[$_] > $data[$max] }
    There's no point in comparing the first element to itself.

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