Beefy Boxes and Bandwidth Generously Provided by pair Networks
"be consistent"
 
PerlMonks  

Re: How to answer "Perl is not secure" objections?

by Anonymous Monk
on Sep 06, 2007 at 23:36 UTC ( #637556=note: print w/ replies, xml ) Need Help??


in reply to How to answer "Perl is not secure" objections?

Hi radiantmatrix,

manager^2 and manager^3 are squaring and cubing the 'r' respectively. I think you meant:

(manager)^2 and (manager)^3
The lone manager is understood to have an exponent of 1.

;-D

~DigitalKitty
Too lazy to log in.


Comment on Re: How to answer "Perl is not secure" objections?
Select or Download Code
Re^2: How to answer "Perl is not secure" objections?
by CountZero (Bishop) on Sep 07, 2007 at 16:48 UTC
    DigitalKitty,

    Are you sure ^ binds stronger than the characters within a word?

    CountZero

    A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James

Re^2: How to answer "Perl is not secure" objections?
by tilly (Archbishop) on Sep 07, 2007 at 18:25 UTC
    How does the xor operator result in exponentiation? Did you mean ** instead??

    :-P

Log In?
Username:
Password:

What's my password?
Create A New User
Node Status?
node history
Node Type: note [id://637556]
help
Chatterbox?
and the web crawler heard nothing...

How do I use this? | Other CB clients
Other Users?
Others romping around the Monastery: (7)
As of 2014-08-22 05:42 GMT
Sections?
Information?
Find Nodes?
Leftovers?
    Voting Booth?

    The best computer themed movie is:











    Results (147 votes), past polls