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Perl: the Markov chain saw

Re: Yesterday Date

by mifflin (Curate)
on Feb 04, 2008 at 20:18 UTC ( #666086=note: print w/ replies, xml ) Need Help??

in reply to Yesterday Date

Possible pure Perl solution...

my $wday = (localtime)[6]; my $offset = $wday == 1 ? 3 : ($wday == 0 ? 2 : 1); my @date = localtime(time - 86400*$offset); printf "%s-%s-%s\n", 1900+$date[5], 1+$date[4], $date[3];
Doesn't take into account holidays, just weekends.

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Re^2: Yesterday Date
by vlademonkey (Pilgrim) on Feb 04, 2008 at 20:56 UTC
    Also doesn't take into account Daylight_saving, where a day can be 25 hours long. As others stated, using a well-tested CPAN library is your best bet with date manipulation.

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