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Re: Regexp - groupings

by harleypig (Monk)
on Aug 02, 2008 at 23:14 UTC ( #701855=note: print w/replies, xml ) Need Help??

in reply to Regexp - groupings

I get the following:
DB<1> x split /(a|b)+/, '12aba34ba5' 0 12 1 'a' 2 34 3 'a' 4 5
If I change that to:
DB<8> x split /(a|b|c|d|e)+/, '12abc34de5' 0 12 1 'c' 2 34 3 'e' 4 5
So, it's only capturing the last delimiter. If you do a regex the same way you get the same thing:
DB<12> x '12abc34de5' =~ /(a|b|c|d|e)+/g 0 'c' 1 'e'
Interesting. I'm not sure why. Maybe it has something to do with a list being returned in a scalar context (the last element is captured that way). If you want to capture the whole delimiter you need to put the + inside the parens:
DB<16> x split /([abcde]+)/, '12abc34de5' 0 12 1 'abc' 2 34 3 'de' 4 5
Harley J Pig

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[shmem]: grandola vila morena *sing*
[Discipulus]: are you sharing your memory? ;=) and ++
[shmem]: Discipulus of course ;-)
[LanX]: shmem I upvoted your reply ... for sympathy only
[LanX]: ;)
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