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Re: Re: sort mechanism

by extremely (Priest)
on Apr 06, 2001 at 23:17 UTC ( #70563=note: print w/ replies, xml ) Need Help??

in reply to Re: sort mechanism
in thread sort mechanism

No that doesn't work. The parens basically are no-ops there. a scalar is just a scalar. You would need @{$a} to explode the array.

update (GOOD band names =)

$you = new YOU;
honk() if $you->love(perl)

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Re: Re: Re: sort mechanism
by McD (Chaplain) on Apr 06, 2001 at 23:32 UTC
    Um... right. I don't think I was completely clear - what I was trying to point out was that <=> has different behavior when comparing lists than when comparing scalars.

    Although comparing two lists of a single scalar each is, as you said, exactly like comparing the naked scalars.

    So what have we learned?

    1. I shouldn't node before coffee, no matter what the hour.
    2. "Naked Scalars" would be a pretty good name for a rock and roll band.
    3. So would "Spaceship Operator."
    4. I still can't find where <=>'s behavior in list context is documented.
      The equality operators apply scalar context to both sides. Try this out and see. Operators apply context. I don't think they often respond to it but with perl anything is possible =)
      my @a = keys %env; my @b = values %env; my @c = ( "equal", "a > b", "b > a" ); print ($c[@a<=>@b]),$/;

      No really, damn good band names... =)

      $you = new YOU;
      honk() if $you->love(perl)

        Ok, then riddle me this:

        #!/usr/local/bin/perl -l my @a = (1, 2, 3); my @b = (1, 2, 4); my @c = ( "equal", "a > b", "b > a" ); print ($c[@a<=>@b]); print ($c[@b<=>@a]); print ($c[(1, 2, 3)<=>(1, 2, 4)]); print ($c[(1, 2, 4)<=>(1, 2, 3)]);


        b > a
        a > b
        Something about the difference between an array and a list, I suspect - a distinction oft unclear in my mind, regardless of caffine levels.


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