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Re: Re: Re: Re: sort mechanism

by extremely (Priest)
on Apr 07, 2001 at 00:01 UTC ( #70577=note: print w/ replies, xml ) Need Help??


in reply to Re: Re: Re: sort mechanism
in thread sort mechanism

The equality operators apply scalar context to both sides. Try this out and see. Operators apply context. I don't think they often respond to it but with perl anything is possible =)

my @a = keys %env; my @b = values %env; my @c = ( "equal", "a > b", "b > a" ); print ($c[@a<=>@b]),$/;

No really, damn good band names... =)

--
$you = new YOU;
honk() if $you->love(perl)


Comment on Re: Re: Re: Re: sort mechanism
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Something Strange is Afoot Here
by McD (Chaplain) on Apr 07, 2001 at 00:36 UTC
    Ok, then riddle me this:

    #!/usr/local/bin/perl -l my @a = (1, 2, 3); my @b = (1, 2, 4); my @c = ( "equal", "a > b", "b > a" ); print ($c[@a<=>@b]); print ($c[@b<=>@a]); print ($c[(1, 2, 3)<=>(1, 2, 4)]); print ($c[(1, 2, 4)<=>(1, 2, 3)]);

    Produces:

    equal
    equal
    b > a
    a > b
    
    Something about the difference between an array and a list, I suspect - a distinction oft unclear in my mind, regardless of caffine levels.

    Peace,
    -McD

      A LIST in SCALAR context returns its last item. An ARRAY in SCALAR context returns its count.

      A LIST in ARRAY/LIST context returns a LIST. An ARRAY in ARRAY/LIST context returns a LIST.

      That gets just about everyone at one time or another. It flat *BOGGLED* me for a while. Try this: perl -e 'print scalar( (1,2,3,4) ),$/'

      --
      $you = new YOU;
      honk() if $you->love(perl)

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