|Do you know where your variables are?|
Re^5: If you believe in Lists in Scalar Context, Clap your Handsby ikegami (Pope)
|on Oct 24, 2008 at 18:54 UTC||Need Help??|
How do you reconcile that with the fact that both the array and the array slice perform exactly the same action in list context: they put their members on the stack. Either they both make a list or neither does.
I bolded the mistake. Just like the right-hand ** doesn't return 3 in 2**3**4, The right-hand assignment doesn't return ($a, $b) in $r = ($a, $b) = 0..11. A list assignment in scalar context returns the number of items it was given to assign. 12, in this case.
There are two different sort of value. Three even.
I wouldn't say it has integer context, because that would imply a parallel with scalar vs list context. Scalar and list context force operands to returns a scalar and a list respectively. Integer coercion doesn't force operands to returns an integer.
Let's look at an example. Given f() % 3, f() is executed in scalar context and in "integer context".
Your argument relies on the premise of a parallel between scalar context and integer coercion, but it's very clear there isn't one. The premise is false, so the argument is moot.
This isn't relevant, but I thought you'd be interested in an additional difference: some operators (such |, & and ^) behave differently based on whether they're given a string or an integer. Some operators behave differently based on the length of the list they are given, but you won't find an operator that can accept both a scalar and a list.
Update: Formatting changes. Minor typo correction.