http://www.perlmonks.org?node_id=722005


in reply to Re^4: How do I pretend a reference isn't a reference
in thread How do I pretend a reference isn't a reference

That's not what my code does, nor was I saying that $c was one thing at compile time and one at run time. This is what I do:

# init the app sub _ { 'compile time '.@_}; my $compile = _(1); sub foo { _(1) }; # finished compiling, so redefine sub _ sub _ { 'run time '.@_}; # run the code my $run = foo(); print " $compile - $run\n" __END__ compile time 1 - run time 1
UPDATE: Meant to reply to Re^5: How do I pretend a reference isn't a reference