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qw// in Perl 5.6

by Eureka_sg (Monk)
on Apr 16, 2001 at 07:26 UTC ( #72759=note: print w/ replies, xml ) Need Help??


in reply to Re: NEWBIE Brain Teaser #2, by nysus
in thread NEWBIE Brain Teaser #2, by nysus

I believe that qw// no longer use split in 5.6. Instead, it's using the comma-operator. As a result, you are just trying to assign a list to a scalar. Thus, $_ will just hold 'nothing' and the answer for part c is "In the beginning there was alpha, in the end there will be omega."

Disclaimer: I don't have 5.6 installed, so the above is pure speculation. Pls correct me if I'm wrong. : )


Comment on qw// in Perl 5.6
Re: qw// in Perl 5.6
by nysus (Deacon) on Apr 16, 2001 at 15:12 UTC
    Actually, with version 5.005, the script yields: "In the beginning there was nothing, in the end there will be nothing."

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