Re: [Perl6] Sort a hash by value

[moritz]

in reply to [Perl6] Sort a hash by value

my %nums = (
  four  => 4,
  one   => 1,
  three => 3,
  two   => 2,
);

for %nums.pairs.sort: { $^a.value <=> $^b.value } -> $pair {
    say $pair;
}

(not necessarily shorter, but mentions %nums only once in the sort line).

There was also a proposal to make the sort method accept a block of arity one that automatically performs a ST, but it doesn't seem to be in the spec, and thusly isn't implemented by Rakudo right now.

Update: clinton asked in the CB what the colon after the sort was about, so here's the explanation for everybody: The are two syntax forms for method calls in Perl 6, $object.method($arg1, $arg2, ...) and $object.method: $arg1, $args, .... My example uses the latter to avoid more parenthesis.

[haoess]

There was also a proposal to make the sort method accept a block of arity one that automatically performs a ST, but it doesn't seem to be in the spec, and thusly isn't implemented by Rakudo right now.

Thanks to pmichaud++, now it is (he says).

Update: Here's his blog entry.

-- Frank