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Think about Loose Coupling

I'm me but I'm not me...

by Minok (Novice)
on Apr 23, 2009 at 00:16 UTC ( #759452=request: print w/replies, xml ) Need Help??

So I didn't follow rule #1 and needed to add to my post, only to discover there was no handle by which to do that.

The post ( is made by Minok (me), but its just presented as posted by Minok, and I cannot edit it (as if Minok is not me).

Q&A > arrays > How do I completely remove an element from an array? contributed by Minok

I then proceeded to reply to my own post to add what I wanted to add and see that that post ( is indeed recognized as 'me':

Re: Answer: How do I completely remove an element from an array?
by you!!!

So I'm not sure what happened.. if this is a system issue or me not understanding the interface.

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[Discipulus]: always! but if i can ask choroba why you always use the inverted (to me) form 1 == $.?
[choroba]: To avoid accidental overwriting of the variable in if ($x = 3)
[karlgoethebier]: Corion: Auch in hessisch? Mer wasses net.
[Corion]: Hmm - I'm not sure, I haven't read the mundart/slang translations ;)
[Eily]: $F[1] =~ s/^0//r could be written as (0+$F[1]). It's less explicit though
[Discipulus]: ah! seems wise choroba, you play safe
[shmem]: Eily: also -+-$F[1]
[shmem]: hmm... there should be a glyph for "bembel" in unicode "miscellaneous symbols"

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