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Re: why the array index has to start at 0??by moritz (Cardinal) 
on Jun 23, 2009 at 10:39 UTC ( #773958=note: print w/ replies, xml )  Need Help?? 
And if you then find an algorithm where it's the other way round, you can still leave the first item empty and work as if you had 1based indexes, with minimal overhead. Doing it the other way round (ie emulating 0based indexes with 1based indexes) would involve an arithmetic operation on every array access. But in the end it's a topic where you can have very strong opinions about, and no amount of arguing will convince you in the end. Like coding style. Update: I thought a bit more about, and came to the conclusion that more integer operations as performed by the CPU stay within range if your numbers start from 0, not from 1: resulting range if numbers Operation start from 0 start from 1 Comment * 0..Inf 1..Inf No difference / 0..Inf(*) 0..Inf 0 better + 0..Inf 2..Inf 0 better  Inf..Inf Inf..Inf No difference % 0..Inf(*) 0..Inf 0 better ** 0..Inf(*) 1..Inf No difference (*): some operations disallowed So you see that if your numbers are start from 0, more operations have identical domain (for the left operand) and codomain, at the cost of having some disallowed operations for 0 as the right operand (like 1/0, and 0**0). IMHO that's a plus for choosing 0 as the start. It also feels nice to have the neutral element of addition inside the range.
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