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Re^5: What is happening ?

by grizzley (Chaplain)
on Aug 19, 2009 at 08:11 UTC ( #789727=note: print w/replies, xml ) Need Help??

in reply to Re^4: What is happening ?
in thread problem using foreach and each with hash ref

No.each works with while, and for works with keys. Corrections: Re^6: What is happening ? and Re^7: What is happening ?

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Re^6: What is happening ?
by Anonymous Monk on Aug 19, 2009 at 08:56 UTC
    Actually :)
    #!/usr/bin/perl -- use strict; use warnings; my %f = 1 .. 4; for( ; my($k,$v) = each %f ; ){ print qq!($k)=($v)\n!; } __END__ (1)=(2) (3)=(4)
    But B::Deparse reveals
    use warnings; use strict 'refs'; my(%f) = 1..4; while (my($k, $v) = each %f) { do { print "($k)=($v)\n" }; } __DATA__
    So I'm not sure :D
      Ok, I give up, I will disprove the other half of my thesis by myself :)
      %f=1..4; while(($k)=keys%f) { print qq!($k)=($f{$k})\n!; delete $f{$k} }

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