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Re^2: Mini-Tutorial: Scalar vs List Assignment Operator

by ikegami (Pope)
on Aug 20, 2009 at 17:12 UTC ( #790146=note: print w/replies, xml ) Need Help??


in reply to Re: Mini-Tutorial: Scalar vs List Assignment Operator
in thread Mini-Tutorial: Scalar vs List Assignment Operator

Thanks. Fixed.

Yes, there's nothing special about lvalue subs. f() doesn't cause the list assignment operator to be used, but (f()) does.

$ perl -wle'sub f :lvalue { $x,$y } f()=(4,5); print $x,$y' Useless use of a constant in void context at -e line 1. Use of uninitialized value in print at -e line 1. 5 $ perl -wle'sub f :lvalue { $x,$y } (f())=(4,5); print $x,$y' 45

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