in reply to calculator script
The problem is ,in the following .
Here you are checking the number of arguments is five.
So it will fail if you are giving input in the following format.
1 + 2 3
So that time you need to check the number of arguments is equal to four.
If you want to give input like,
1 + 2 + 3
then that time you need to check the number of arguments is equal to five.And you need to change the following part of code also.
your code,
These changes are needed only in the case of if you are giving input in the format 1 + 2 + 3 .
$nbArguments = $#ARGV + 1; print "number of arguments: $nbArgumentsn"; exit(1) unless $nbArguments == 5;
Here you are checking the number of arguments is five.
So it will fail if you are giving input in the following format.
1 + 2 3
So that time you need to check the number of arguments is equal to four.
If you want to give input like,
1 + 2 + 3
then that time you need to check the number of arguments is equal to five.And you need to change the following part of code also.
your code,
Change into,$a = $ARGV[0]; $operation = $ARGV[1]; $b = $ARGV[2]; $c = $ARGV[3]
$val1 = $ARGV[0]; $operation1 = $ARGV[1]; $val2 = $ARGV[2]; $operation2 = $ARGV[3] $val3=$ARGV[4]
These changes are needed only in the case of if you are giving input in the format 1 + 2 + 3 .
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