Re: two + 2 not equal 4!

[toolic]

Tip #6 from the Basic debugging checklist: use B::Deparse to see if your code really is what you think it is:

$ perl -MO=Deparse two.pl

BEGIN { $^W = 1; }
sub two {
    use strict 'refs';
    2;
}
use strict 'refs';
printf "two + 2 = %d\n", two(2);

So, two + 2 is interpreted as two(2). Instead of evaluating your function, then adding 2, perl treats everything after your function call as a LIST of arguments when you omit the parentheses. From perlsub:

2. NAME LIST; # Parentheses optional if predeclared/imported.

While it is legal syntax to omit the parentheses on function calls, it is a good practice to use them, even if your function does not need arguments:

printf "two + 2 = %d\n",two() + 2;

As a side note, your code would render better if you replace your "pre" tags with "code" tags: Writeup Formatting Tips