I think you need to read our responses more carefully. Corion
gave you most of the answer, and I helped you with the substitution, noting in my response: "...which you would apply line by line as you read through the file
". If you don't understand what Corion
wrote, then ask a specific question, but please don't just ignore the advice. As you seem to need a little more fundamental guidance, I'll say this: Perl will let you do what you want in many
possible ways, but a basic approach to run your code in a file (your script.pl) from the Perl command line as you appear to have chosen, that code will have to:
- open the input file (tip: check out the "null filehandle" in perlop)
- read lines one by one,
- apply the substitution regex you want, and
- write the result somewhere. Your output could go to the console, pipe to a file, get written to a file you opened in your code, or you could even investigate Perl's handy feature for editing a file in place via the -i command line option (read up on this in perlrun).
All your code (and please do use code tags - see Writeup Formatting Tips
just above the editing box when you're composing your message) does is apply a substitution to nothing and ends, so of course you get no result.
Quick tips on your regex modification: The colon has no special meaning so you need not put it in square brackets. Functionally there is no difference, but using unnecessary characters makes it harder for others to easily pick out what you mean to do. Also, unless you want to accept cases of more than one colon, don't put a + after the colon. Please read up on regular expressions; the + symbol is not used to assemble parts of a regex, it is a quantifier and means 'match one or more of the preceding element'.
I'd like to be able to assign to an luser