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Re^2: how to always round up in perl?

by chrestomanci (Priest)
on Feb 25, 2011 at 09:19 UTC ( #890150=note: print w/ replies, xml ) Need Help??


in reply to Re: how to always round up in perl?
in thread how to always round up in perl?

That fails if $n is allready an integer. You would need something like:

my $n = 3.0; my $ceiling = int($n); $ceiling += 1 if $ceiling != $n;

Or as a one liner:

my $ceiling = int($n) + ($n != int($n));


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