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Re^2: Why won't say act like say when its tied?

by ELISHEVA (Prior)
on Mar 07, 2011 at 17:51 UTC ( #891871=note: print w/ replies, xml ) Need Help??


in reply to Re: Why won't say act like say when its tied?
in thread Why won't say act like say when its tied?

print appends the value of $\ to the end of whatever is passed to print, so if $\="***\n", then {print "hello", "\n"; } outputs "hello\n***\n" not plain "hello\n". That's why it is important for say to set local $\="\n" and not just add "\n" to the end of the list of things to print. Hope that helps.


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Re^3: Why won't say act like say when its tied?
by Anonymous Monk on Mar 07, 2011 at 19:45 UTC
    Thanks, it does. So the intended behavior for say is to write exactly what the programmer intended plus \n without side effects from punctuation variables. Good to know.

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