Re^2: Why won't say act like say when its tied?

[ELISHEVA]

in reply to Re: Why won't say act like say when its tied?
in thread Why won't say act like say when its tied?

print appends the value of $\ to the end of whatever is passed to print, so if $\="***\n", then {print "hello", "\n"; } outputs "hello\n***\n" not plain "hello\n". That's why it is important for say to set local $\="\n" and not just add "\n" to the end of the list of things to print. Hope that helps.

[Anonymous Monk]

Thanks, it does. So the intended behavior for say is to write exactly what the programmer intended plus \n without side effects from punctuation variables. Good to know.