http://www.perlmonks.org?node_id=907289


in reply to what does $|++ do here?

Noting also the comment about it being a toggle, the ++ doesn't make sense to me either. But in that case, I would tend to wonder if the following is what is really meant: 
$| = !$|;

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Which is a good enough reason otherwise to support the above idea of just assigning one to it to avoid confusion.

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Re^2: what does $|++ do here?
by ikegami (Patriarch) on May 31, 2011 at 18:01 UTC
    It was said that --$| toggles $|. While $| = !$|; is clearer than --$|, noone said anything about wanting to toggle $|.
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