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Cannot find input arguments to program called with "system"

by pktrain (Acolyte)
on Jul 06, 2011 at 05:52 UTC ( #912913=perlquestion: print w/replies, xml ) Need Help??
pktrain has asked for the wisdom of the Perl Monks concerning the following question:


I'm writing a Perl script to run an external program on every file in a directory. This program converts files from one format to another. Here's the deal...

When I run the program from the command line, everything works as it should: % /path/program /inpath/ /outpath/output.out converting: /inpath/ to /outpath/output.out %

Here's the code I wrote to convert all files in a directory (listed in "file_list.txt"):

#!/usr/bin/perl -w use warnings; use diagnostics; use FileHandle; use File::Copy; # Set simulation parameters and directories @test_dates = ("20110414"); $listfile = "file_list.txt"; $execname = "/path/program"; foreach $date (@test_dates) { # Set/make directories $obs_file_dir = "inpath"; $pred_file_dir = "outpath"; mkdir "$pred_file_dir", 0755 unless -d "$pred_file_dir"; # Read input file names to array $obs_file_list = $obs_file_dir . $listfile; open(DIR, $obs_file_list) or die "Could not open file!"; @obs_files = <DIR>; close(DIR); # Convert and save files foreach $file (@obs_files) { $file =~ s/(\*)//g; $infile = $obs_file_dir . $file; $outfile = $pred_file_dir . $file; $outfile =~ s/nid/cdf/g; print $infile . "\n"; @arg_list = ($execname, $infile, $outfile); system(@arg_list); } }

The output shows me the following error for every file in the list: % /inpath/ converting: /inpath/ to /outpath/output.out unable to find /inpath/ stat status=-1 error while processing the product

I verified every file is in the proper place and have no idea why I am getting this error. Your advice is greatly appreciated!

Replies are listed 'Best First'.
Re: Cannot find input arguments to program called with "system"
by philipbailey (Chaplain) on Jul 06, 2011 at 07:07 UTC

    You should chomp $file. It otherwise contains a newline character at the end.

      Thank you! Using chomp() was the solution...
Re: Cannot find input arguments to program called with "system"
by Khen1950fx (Canon) on Jul 06, 2011 at 07:07 UTC
    Your biggest problem was not declaring your lexical variables with 'my'. I fixed that and made a few changes.
    #!/usr/bin/perl use strict; use warnings; my(@test_dates) = '20110414'; my $listfile = '/root/Desktop/Log.txt'; foreach my $date(@test_dates) { my $obs_file_dir = 'inpath'; my $pred_file_dir = 'outpath'; mkdir "$pred_file_dir", 0755 unless -d "$pred_file_dir"; my $obs_file_list = $listfile; open( DIR, '<', $obs_file_list ) or die $!; my(@obs_files) = <DIR>; close(DIR); foreach my $file(@obs_files) { $file =~ s/(\*)//g; my $infile = $obs_file_dir . $file; my $outfile = $pred_file_dir . $file; $outfile =~ s/nid/cdf/g; print $infile . "\n"; } }

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