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Re: variable constructs that I do not understand

by wink (Scribe)
on Sep 06, 2011 at 21:42 UTC ( #924470=note: print w/replies, xml ) Need Help??

in reply to variable constructs that I do not understand

Perl allows you to use the value of one scalar as the identifier for another. Rarely is it a good idea, but occasionally it is useful.

$var = 'foo'; $foo = 'bar'; print $var; # Will print "foo" print $$var; # Will print "bar"
Also, you can use curly braces around a variable when it might be confusing to the compiler what you mean.
$foo = 'foo'; print "$food"; # Will print nothing (no scalar $food is defined) print "${foo}d"; # Will print 'food' as expected

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