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why do I have to provide context to split result in a separate statement?

by Mark_Galeck (Novice)
on Sep 21, 2011 at 00:38 UTC ( #927040=perlquestion: print w/ replies, xml ) Need Help??
Mark_Galeck has asked for the wisdom of the Perl Monks concerning the following question:

Hello, why does this bomb
print @{\(@arr = split / /, '')}
while this does not
@arr = split / /, ''; print @{\@arr}
Thank you, Mark

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Re: why do I have to provide context to split result in a separate statement?
by jwkrahn (Monsignor) on Sep 21, 2011 at 01:40 UTC

    \(@arr = split / /, '') returns a list of references.

    For example \( $a, $b, $c ) is actually ( \$a, \$b, \$c ) and you can't dereference that as an array.

    What you could do is copy the list to an anonymous array:

    print @{[@arr = split / /, '']}
      Don't need to copy it into two arrays.
      print @{[ split / /, '' ]}
        Thank you very much!

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