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Re^2: help on this code below

by sasidhardv (Initiate)
on Oct 27, 2011 at 18:24 UTC ( #934208=note: print w/replies, xml ) Need Help??


in reply to Re: help on this code below
in thread help on this code below

what does this mean if ($query->param($key) =~ /([^\/\\]+)$/) { # is this removing spaces ??
and
next if ($key !~ /^filetoupload_(\d+)$/);
especially (\d+)$/ mean

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Re^3: help on this code below
by hbm (Hermit) on Oct 27, 2011 at 18:52 UTC
    what does this mean if ($query->param($key) =~ /([^\/\\]+)$/) { # is this removing spaces ??

    The square brackets enclose a character class. The first character in that class is a caret, which negates the class. Each initial backslash escapes the following character. The plus sign matches one or more. The parentheses store whatever is matched. The dollar matches the end of the line. Putting it all together, "if parameter ends with one or more non-slashes, give me those non-slashes in $1.

    This is matching only - no substitution.

    and next if ($key !~ /^filetoupload_(\d+)$/); especially (\d+)$/ mean

    \d matches a digit. Here, caret matches the start of the string. Everything else is described above. Putting it together, if $key starts with "filetoupload_" and ends with digits, give me those digits in $1.

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