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Re^3: new to perl, syntax question

by tangent (Vicar)
on Feb 20, 2012 at 13:50 UTC ( #955072=note: print w/replies, xml ) Need Help??

in reply to Re^2: new to perl, syntax question
in thread new to perl, syntax question

Aagh - I did try it before I replied but like this:
print @name . "\n";
then I took the "\n" out to make it clearer (but didn't run it!). I take it the concatenation makes print evaluate in scalar context. So should be:
print "@name"; # prints x y z print @name; # prints xyz print @name . "\n"; # prints 3
(lidden: I was still fixing this when you replied)

Update - then I found this:
If you believe in Lists in Scalar Context, Clap your Hands
I'll be back in a few weeks.

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Re^4: new to perl, syntax question
by lidden (Curate) on Feb 20, 2012 at 13:56 UTC
    Concatenation puts its arguments in scalar context, that is the array is in scalar context.

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