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Re: Doing pair-exclusivity analysis and building a matrix

by tangent (Priest)
on Mar 28, 2012 at 02:25 UTC ( #962050=note: print w/replies, xml ) Need Help??


in reply to Doing pair-exclusivity analysis and building a matrix

This is probably a bit long-winded but does seem to work:
my (@names,%hash,%matrix); while (my $line = <DATA>) { chomp($line); my ($name,$list) = split(m/\s+/,$line); push(@names,$name); $hash{$name} = [ split(',',$list) ]; } for my $name (@names) { my $countries = $hash{$name}; for my $name2 (@names) { my $diff = get_diff($countries,$hash{$name2}); push( @{ $matrix{$name} }, $diff ); } } sub get_diff { my ($x,$y) = @_; my (%union,%isect); for my $item (@$x,@$y) { $union{$item}++ && $isect{$item}++; } return scalar @$x - scalar keys %isect; } print "ID\t" . join("\t",@names) . "\n"; for my $name (@names) { print "$name\t" . join("\t", @{ $matrix{$name} } ) . "\n"; } __DATA__ Name1 USA,Canada,Yemen Name2 Canada,Portugal,India Name3 China,HongKong,Canada Name4 London,Amsterdam,Ireland,USA Name5 India,USA,Canada
Output:
ID Name1 Name2 Name3 Name4 Name5 Name1 0 2 2 2 1 Name2 2 0 2 3 1 Name3 2 2 0 3 2 Name4 3 4 4 0 3 Name5 1 1 2 2 0

Replies are listed 'Best First'.
Re^2: Doing pair-exclusivity analysis and building a matrix
by angerusso (Novice) on Mar 28, 2012 at 02:46 UTC
    THANK YOU SO MUCH!!! Wow, thanks so much for your quick reply and it works beautifully!~

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