Re: Timelocal, Localtime Bug?

[jwkrahn]

$ perl -le'my $test = localtime( 0, 0, $month, 1, 31, 2012 ); print $t
+est'
Too many arguments for localtime at -e line 1, near "2012 )"
Execution of -e aborted due to compilation errors.

Your code won't even compile, let alone run.

[Riales]

It looks like it might run if you flip localtime and timelocal with each other (I'm guessing timelocal takes the arguments localtime is currently taking and vice-versa).

That said, I have no idea concerning the original question. ><

[alanonymous]

Sorry guys! My development machine is not connected to the internet, so I had to type the chunk of applicable code and I mixed up timelocal and localtime. I fixed the code samples in the original post, so now my original question actually applies (also put 3 instead of 31... I hate fat fingers today). Sorry!