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Re^4: Introducing MooseX::hasn't

by tobyink (Abbot)
on Apr 03, 2012 at 13:14 UTC ( #963241=note: print w/ replies, xml ) Need Help??


in reply to Re^3: Introducing MooseX::hasn't
in thread Introducing MooseX::hasn't

No, polymorphism doesn't depend on inheritance, and I never claimed that it did. Polymorphism is generally an expected outcome of inheritance though. There are clearly other ways of allowing polymorphism though - roles as you say; also mocking, delegation, etc.

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'


Comment on Re^4: Introducing MooseX::hasn't
Re^5: Introducing MooseX::hasn't
by Arunbear (Parson) on Apr 03, 2012 at 17:58 UTC
    From the POD:
    The idea behind polymorphism is that if Bar inherits from Foo, then I should be able to use an object of type Bar wherever I'd normally use Foo.
    That makes it sound like you're equating polymorphism with inheritance.

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